如何計算storage上的IOPS

(1 / (average latency in ms + average seek time in ms) -->( 執行一個I/O所花費的時間ms)的倒數

• Model: Western Digital VelociRaptor 2.5″ SATA hard drive
• Rotational speed: 10,000 RPM
• Average latency: 3 ms (0.003 seconds)
• Average seek time: 4.2 (r)/4.7 (w) = 4.45 ms (0.0045 seconds)
• Calculated IOPS for this disk: 1/(0.003 + 0.0045) = about 133 IOPS

參考這裡
MS說明

我的計算方式利用MS裡的avg. Disk sec/Transfer來找IOPS
avg. Disk sec/Transfer = 0.012 ms (花了0.012ms執行了一個I/O)
1/0.012 = 83 IOPS (那一秒可以執行83次I/O)